SOLUTION: A bacteria colony grows continuously at an exponential rate. There are initially 1.6 million present. After 4 days, there are 6.6 million present.
a. What is an equation model
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Question 1005068: A bacteria colony grows continuously at an exponential rate. There are initially 1.6 million present. After 4 days, there are 6.6 million present.
a. What is an equation modeling the number of bacteria present after "d" days?
b. How many bacteria will be present after 9 days?
c. How long will it take the number of bacteria to reach 90 million?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
\ =\ ae^{kd})
\ =\ ae^0\ =\ 1.6\ \Rightarrow\ a\ =\ 1.6)
\ =\ 1.6e^{4k}\ =\ 6.6)
\ =\ \ln(6.6)\ -\ \ln(1.6))
\ -\ \ln(1.6))
\ -\ \ln(1.6)}{4})
Do the arithmetic to calculate the value of 
b. Calculate )
c. Set \ =\ 90)
and then solve for 
John
My calculator said it, I believe it, that settles it
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