SOLUTION: Sanchez has a collection of pennies, nickels, and dimes worth $9.35. He has five more nickels than pennies and twice as many dimes as pennies. How many coins of each kind does he h

Question 1004424: Sanchez has a collection of pennies, nickels, and dimes worth $9.35. He has five more nickels than pennies and twice as many dimes as pennies. How many coins of each kind does he have?

Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
.01p+.05n+.10d= 9.35
n= p+5
d= 2p
Let's rewrite the initial equation substituting the values of n and d:
.01p+.05(p+5)+.10(2p)= 9.35 Multiply on left to eliminate parentheses:
.01p+.05p+.25+.20p= 9.35 Add p on left and subtract .25 on both sides:
.26p= 9.10 Divide both sides by .26
p= 35 We have 35 pennies
5 more nickels than pennies: 35+5= 40 nickels
2 times more dimes than pennies: 35*2= 70 dimes
Proof
35*.01= .35
40*.05= 2.00
70*.10= 7.00
_ _ _ _------
Total....9.35 We have the correct answer
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