SOLUTION: The sum of three numbers is
129
. The third number is
4
times the first. The first number is
9
more than the second. What are the numbers?
Algebra.Com
Question 1004197: The sum of three numbers is
129
. The third number is
4
times the first. The first number is
9
more than the second. What are the numbers?
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
let the first number be , the second number , and third number
the sum of three numbers is ; so, we have
.....eq.1
if the third number is times the first, we have
if the first number is more than the second, we have
substitute it in eq.1
.....eq.1
now find other two numbers
=>
=>
RELATED QUESTIONS
The sum of three numbers is 114 . The third number is 3 times the first. The second... (answered by ewatrrr)
the sum of three numbers is 66. the third number is 9 more than the first. the second... (answered by timvanswearingen)
The sum of three numbers is
93
. The second number is
2
times the third. The first (answered by Alan3354,josgarithmetic)
The sum of three numbers is 116. The third number is 3 times the second. The second... (answered by stanbon)
The sum of three numbers is 121. The third number is 4 times the first. The first number... (answered by Edwin McCravy,tajar)
The sum of three numbers is 131 . The second number is 4 times the third. The third... (answered by rfer)
The sum of three numbers is 119. The second number is 4 times the third. The third number (answered by Edwin McCravy)
The sum of three numbers is 92. The second number is 10 more than the first. The third... (answered by josgarithmetic)
The sum of three numbers is 144. The second number is 6 more than the first . The third... (answered by CubeyThePenguin)