|
Tutors Answer Your Questions about Geometry Word Problems (FREE)
Question 179079: Mr dean and Mr Tomlin have similar rectangular yards. the area of Mr Tomlin's yard is four times bigger than the area of Mr dean's yard. the length of Mr dean's yard is 15m and the area of Mr Tomlin's yard is 720m square. calculate the cost of fencing for each yard if it costs $15 per meter
Click here to see answer by MissionPossible(18)   |
Question 179253: I need help with these two word problems.
1. The perimeter of a rectangle is 24 centimeters. The lenght of the rectangle is four more than the width. What is the length of the rectangle.
2. The sum of three consecutive even intergers is 444. what are the three numbers.
Click here to see answer by stanbon(26297) |
Question 179253: I need help with these two word problems.
1. The perimeter of a rectangle is 24 centimeters. The lenght of the rectangle is four more than the width. What is the length of the rectangle.
2. The sum of three consecutive even intergers is 444. what are the three numbers.
Click here to see answer by josmiceli(3013) |
Question 180243: A company has determined that the profit, in dollars, it can expect from the manufacture and sale of x tennis racquets is given by: P= -0.01x2 + 168x - 120,000. How many racquets should the company manufacture and sell to earn a profit of $518,000?
Click here to see answer by Mathtut(3670) |
Question 181517This question is from textbook Saxon Algebra 1
: The height h of a cylinder varies in inversely with the area of the base B when the volume is constant. If the height of the cylinder is 6 centimeters when the area of the base is 12 square centimeters. What is the area of the base of the cylidner at right with the same volume?
This question is from textbook Saxon Algebra 1
Click here to see answer by Mathtut(3670) |
Question 182005: An architect is designing an office building that is to be a width of 50 feet, a length of 50 feet, and a height of 100 feet. A scale model of the same building is to have a width of 18 inches, a length of 18 inches, and a height of 36 inches
1. Find the scale factor of the office building to the model.
The answer I got for this one is 1:1:2 but I don't think it's right. And I can't answer the other questions until I understand how to do it.
2. The entrance into the building building is 8 feet high by 7 feet wide. Find the height and width of the entrance on the scale model. Round your answer to one decimal place.
3. Two windows on either side ofthe main entrance measure 3 inches wide and 2 inches high on the scale model. Find the height and the width on the actual building. Round your answer to one decimal space.
4. You want to add a window over the entrance to the building. Determine the size that you want the actual window to be. Then find the size of the window on the scale model.
Click here to see answer by Fombitz(2113)  |
Question 182264: The width of a rectangular painting is two thirds its length. If the perimeter is 60 inches, then what are the length and width?
I know that the formula is P= L2 + W2 but I am dyslexic and the fraction in here is throwing me. I would include what I have done so far but it doesn't even make sense to me.
Click here to see answer by checkley77(7072) |
Question 182264: The width of a rectangular painting is two thirds its length. If the perimeter is 60 inches, then what are the length and width?
I know that the formula is P= L2 + W2 but I am dyslexic and the fraction in here is throwing me. I would include what I have done so far but it doesn't even make sense to me.
Click here to see answer by rapaljer(3625) |
Question 183149: a man has two children, a boy and a girl. the boy is 6 years older than the girl.two years ago the father's age was three times the sum of the children's ages.In eight years the father's age will be ten years greater than the sum of the children's ages.Find the present ages of the man, of the boy,and of the girl.
Click here to see answer by josmiceli(3013) |
Question 183669: I NEED HELP SOLVING THIS WORD PROBLEM. I DID TRY SOMETHING BUT I DON'T THINK IT IS RIGHT. THE QUESTION IS "the length of a rectangular is 5 more than twice its width. it's perimeter is 88 feet. find it's dimensions?" THIS IS WHAT I TRIED:
L=w+5
2L+2w=88
2(W+5)+2w=68
2W+10+2W=68
4W=68-10
4W=58
W=58/4
W=14.5
L=15.5+5=20.5 INCHES
Click here to see answer by stanbon(26297) |
Question 183911This question is from textbook sullivan
: An adjustable water sprinkler that sprays water in a circular pattern is placed at the center of a square field whose area is 1250 square feet. What is the shortest radius setting that can be used if the field is to be completely enclosed within the circle?This question is from textbook sullivan
Click here to see answer by stanbon(26297) |
Question 183969: A farmer sold a square shaped acre with an oak tree outside each corner. The buyer later returned to buy another acre. The farmer was eager to sell, but wanted to retain ownership of the oaks too. The tough part is that the buyer wanted the whole parcel to be square. In other words, you need to find a way to double the size of the plot and keep it square while at the same time leaving the farmer's four oak trees outside the parcel boundaries. Explain your answer in detail.
Click here to see answer by solver91311(5072)  |
Question 183992: The radius of a wheel is 6 inches. How many revolutions will it make if it is rolled a distance of 288[pi]inches?
Find the standard form of the equation of the line whose x-intercept is 4 and whose y-intercept is 2.
help please!
Click here to see answer by solver91311(5072) |
Question 184616This question is from textbook Elem. Algebra & Intermediate Algebra
: A rectangular piece of cardboaard is 2 units longer than it is wide. From each of its corners a square piece 2 units on a side is cut out. The flaps are then turned up to form an open box that has a volume of 70 cubic units. Find the length and width of the original piece of cardboard.
box volume = length x width x height
volume = 70
width = w
length = 2w (2 times the width)
height = 2
box volume would be 70=(x)(2w)(2)???
this gives me 70=4w^2??? this seems very difficult to work with, can you help me figure this problem out? Thank you.
This question is from textbook Elem. Algebra & Intermediate Algebra
Click here to see answer by solver91311(5072) |
Question 185059: Building a ski ramp. Write an inequality in the variable x for the degree measure of the smallest angle of the triangle shown in the figure, given that the degree measure of the smallest angle is at most 30 degrees.
I have no idea how I got the answer but it seems to be x is less than or equal to 30 ... Is this correct? Can someone please explain. I would greatly appreciate your help.
Click here to see answer by solver91311(5072) |
Question 185188: I have a circular diagramme. I draw the first sector,then the second one, which is 2 times bigger than the fist one ,and so on, to finally divide the whole diagramme. If we double the previous sector 6 times, find the value of the angle at the middle of the inital sector. PLEASEEEEEEEEEEEEEEE HELPPPPPPPPPPPPPPPP PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE HELPPPPPPPPPPPPPPPPPPP''
Click here to see answer by vleith(1977) |
Question 185187: ``I have a circular diagramme. I draw the first sector,then the second one, which is 2 times bigger than the fist one ,and so on, to finally divide the whole diagramme. If we double the previous sector 6 times, find the value of the angle at the middle of the inital sector.
Click here to see answer by solver91311(5072) |
Question 185243: Can you please help me with this word problem for some reason Im not understanding the concept of figuring these problems.
The lenght of a rectangular picture is 5 inches greater thatn twice the width. If the perimeter is 112 inches, find the dimensions of the frame.
thanks,
Click here to see answer by stanbon(26297) |
Question 185243: Can you please help me with this word problem for some reason Im not understanding the concept of figuring these problems.
The lenght of a rectangular picture is 5 inches greater thatn twice the width. If the perimeter is 112 inches, find the dimensions of the frame.
thanks,
Click here to see answer by ankor@dixie-net.com(6693)  |
Question 185501: The original problem was:
[A photo is 4 inches longer than it is wide. A 3-inch border is placed around the photo making the total area of the photo and border 165 square inches. What are the dimensions of the photo? ]
So the initial question was…what was the dimensions of the photo. Since the total area of the photo AND border was 165 square inches, logically the
Total Area of Border and Photo (R3) = 165 square inches or the sum of the Area of the Border (R2) and Photo (R1).
So if I want to find the area of the photo the equation should read R3 - R1 = R2 since the total area of 165 subtracting the area of the photo should allow us to solve for the border and then substitute for w.
Let w = width of photo and w + 4 = length of photo so that the dimensions will equal (w)(w+4) = R1
The area of the border can be seen as the added areas of smaller rectangles surrounding the photo. So that :
x +4 + 6 (3) Each long rectangle = (3x + 30) x 2
3x (x)(x+4) 3x Each smaller rectangle = (3x) x 2
x + 4 + 6 (3)
Therefore the area of the border is represented by 6x + 60 + 6x or 12x + 60
The whole equation can be seen as:
165 – area of photo = area of border or
165 – (x2 + 4x) = 12x + 60, using addition principle combine like terms
165 – x2 - 4x = 12x + 60 becomes 0 = x2 +16x -105
And this is where I get stuck because I cant find the factors of 16 and 105 that make this equation solvable?
Can you please show me the solution to this problem so that I understand.
Click here to see answer by Earlsdon(4900) |
|
Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745
|
| |
