SOLUTION: the length of a rectangle is 1 inch less than twice that of its width. If the perimeter measures 49 inches, then find the dimensions of the rectangle.
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Question 993674: the length of a rectangle is 1 inch less than twice that of its width. If the perimeter measures 49 inches, then find the dimensions of the rectangle.
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
L = 2W - 1
P = 2L + 2W = 49
Now substituting, we get
2(2W - 1) + 2W = 49
4W - 2 + 2W = 49
Simplifying we get
6W = 51 and
W = 8.5
Then
L = 2W - 1 = 2(8.5) - 1 = 17 - 1 = 16
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