SOLUTION: The length of a rectangle is one less than twice the rectangle's width. The rectangle's area equals 703 in^2. Find the rectangle's width (in inches)

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Question 993402: The length of a rectangle is one less than twice the rectangle's width. The rectangle's area equals 703 in^2. Find the rectangle's width (in inches)
Answer by macston(5194)   (Show Source): You can put this solution on YOUR website!
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W=width; L=length=2W-1
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A+LW
703in^2=(2W-1)(W)
703=2W^2-W
0=2W^2-W-703
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=5625 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 19, -18.5. Here's your graph:

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ANSWER: The width is 19 inches.
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