SOLUTION: A Gardener has 60 feet of fencing to enclose a rectangular garden and the two foot wide border surrounding it. If The length of the garden is twice its width, what are its dimen

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Question 98685: A Gardener has 60 feet of fencing to enclose a rectangular garden and the two foot wide border surrounding it.
If The length of the garden is twice its width, what are its dimensions?
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
GARDEN SIDES=X&2X
GARDEN PLUS BORDER=(X+4)&(2X+4)
PERIMETER=2(X+4)+2(2X+4)=60
P=2X+8+4X+8=60
P=6X+16=60
6X=60-16
6X=44
X=44/6
X=7.33 LENGTH OF THE GARDEN
2*7.33=14.66 WIDTH OF THE GARDEN.
PROOF
2(7.33+4)+2(14.67+4)=60
2*11.33+2*18.67=60
22.66+37.24=60
60=60