We are given a right-angled triangle ABC (see the Figure) with the legs |AB| = 8 and |AC| = 16. A square ADEF is inscribed to the triangle ABC in such a way that the triangle and the square have the common right angle LA. We need to find the length of the square side. Let x be the square side length. Then the length of the segment DB is 8 - x and the length of the segment CF is 16 - x. The triangles They have congruent acute angles LFCE and LDEB as these angles are the corresponding angles at the parallel lines AC and DE and the transverse BC. Hence, the triangles Therefore, their legs are proportional: |
Figure |