SOLUTION: One number is one less than twice another, and the difference between squares is 16, find the numbers

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Question 980868: One number is one less than twice another, and the difference between squares is 16, find the numbers
Found 2 solutions by Cromlix, MathTherapy:
Answer by Cromlix(4381)   (Show Source): You can put this solution on YOUR website!
Hi there,
One number is one less than twice another
Another = n
One number = 1 - 2n
the difference between squares is 16
(1 - 2n)^2 - (n)^2 = 16
(1 - 4n + 4n^2) - n^2 = 16
Collect like terms
4n^2 - n^2 - 4n + 1 = 16
3n^2 - 4n - 15 = 0
Factorise
(3n + 5)(n - 3) = 0
So, 3n + 5 = 0
.....n = -5/3
.....n - 3 = 0
......n = 3
Either n = -5/3 and other number = 13/3
or n = 3 and other number = - 5
Hope this helps:-)
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
One number is one less than twice another, and the difference between squares is 16, find the numbers
First number:  

Second number:  

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