SOLUTION: Find the center and radius of the circle with equation, 3x2 + 3y2 - 21x + 6 y + 7 = 0

SOLUTION: Find the center and radius of the circle with equation, 3x2 + 3y2 - 21x + 6 y + 7 = 0

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Question 974306: Find the center and radius of the circle with equation,
3x2 + 3y2 - 21x + 6 y + 7 = 0

Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
3x2 + 3y2 - 21x + 6 y + 7 = 0 ?

3x^2 + 3y^2 - 21x + 6 y + 7 = 0

Complete The Squares:

RHS is

Center is (7/2,-1) and radius seems to be ---- might be computational mistake
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