SOLUTION: A rectangle has a length that is 4 feet greater than its width. If each side of the rectangle is increased by 2 feet, write an equation to represent the area of the new rectangle.

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Question 972882: A rectangle has a length that is 4 feet greater than its width. If each side of the rectangle is increased by 2 feet, write an equation to represent the area of the new rectangle.
Any feedback is appreciated. Confused parent trying to help 15 year old struggling in Math 1.
Thanks in advance!
Found 2 solutions by JoelSchwartz, MathTherapy:
Answer by JoelSchwartz(130)   (Show Source): You can put this solution on YOUR website!
L=original length of the rectangle
w=original width of the rectangle
L=4+w
A=area formula is length times width
(L+2)(w+2)=A
(w+6)(w+2)=A
w^2+6w+2w+12=A
w^2+8w+12=A
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
A rectangle has a length that is 4 feet greater than its width. If each side of the rectangle is increased by 2 feet, write an equation to represent the area of the new rectangle.
Any feedback is appreciated. Confused parent trying to help 15 year old struggling in Math 1.
Thanks in advance!
Let rectangle's width be W

Then its length = W + 4

An increase of 2 feet makes the new width: W + 2

An increase of 2 feet makes the new length: W + 4 + 2, or W + 6

New area = new width, times new length, OR (W + 2)(W + 6)

This expands, by distribution, to:  

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