SOLUTION: the length of the rectangle is 5 inches more than the width. the area is 33 square inches. find the length and width. round to the nearest tenth if necessary.

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Question 966893: the length of the rectangle is 5 inches more than the width. the area is 33 square inches. find the length and width. round to the nearest tenth if necessary.
Answer by amarjeeth123(569)   (Show Source): You can put this solution on YOUR website!
Let the width be x.
Then the length is (x+5).
Area=length*width
x(x+5)=33
x^2+5x-33=0
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=157 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 3.76498204307083, -8.76498204307083. Here's your graph:

x=3.764=3.8
The width is 3.8 units.
The length is 8.8 units.
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