SOLUTION: A photograph has an area of 24 square inches and the length is 2 inches more than the width. Find the length and width of the photograph. If x represents the width of the photog

Question 957764: A photograph has an area of 24 square inches and the length is 2 inches more than the width. Find the length and width of the photograph.
If x represents the width of the photograph, select all the equations that could be used to solve this problem
Found 2 solutions by macston, addingup:
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
W=width; L=length=W+2in; A=area=24 sq in
Substitute for L

Subtract 24 in^2 from wach side.

ANSWER1: The width is 4 inches.
L=W+2in=4in+2in=6in ANSWER 2: The length is 6 inches.
CHECK:

Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
If x represents the width of the photograph, select all the equations that could be used to solve this problem:
L = 2 + W Length equals 2 more than the Width
W = Width
How to solve it:
(2+W)(W) = 24 Multiply on the left to get rid of the parenthesis:
W^2 + 2W = 24 Subtract 24 on both sides:
W^2 + 2W - 24= 0 Now we have a quadratic trinomial we can factor as the product of two binomials. We need four terms, in two pairs of two, such that the first terms multiply to W^2, the outer terms and the inner terms add/subtract to 2W, and the Last terms multiply to -24 (F.O.I.L.):
(W-4)(W+6) = 0 Now we solve for each binomial equation separately:
W-4=0 or W+6= 0 Add 4 on both sides, 1st equation, and subtract 6 on both sides, 2nd equation:
W= 4 or w= -6 We can't use the negative, toss it out and we keep the 4.
Check:
W= 4
L= 2+4= 6
Area: 4*6=24 Our answer is correct.

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