SOLUTION: the base of a triangle exceeds twice its altitude by 18m. If the area of the triangle be360 sq.m . What is its altitude?

Question 957519: the base of a triangle exceeds twice its altitude by 18m. If the area of the triangle be360 sq.m . What is its altitude?

Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
A=area=360 sq m; h=altitude; b=base=2h+18m
Substitute for b.
Multiply each side by 2.
Subtract 720 m^2 from each side

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=6084 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 15, -24. Here's your graph:

h=15m ANSWER: The altitude of the triangle is 15 meters.
CHECK:
b=2h+18m=2(15m)+18m=48m The base of the triangle is 48 meters.
A=1/2bh
360sq m=1/2(48m)(15m)
360 sq m=360 sq m
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