SOLUTION: If the area between 2 squares is 17 inches and the sum of the perimeters of the 2 squares is 68 inches. How many inches long is a side of the larger square?

Question 956760: If the area between 2 squares is 17 inches and the sum of the perimeters of the 2 squares is 68 inches. How many inches long is a side of the larger square?
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
If the following edited question is not what you intended to ask, re-post so someone else can try to interpret.
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If the difference in area between 2 squares is 17 square inches and the sum of the perimeters of the 2 squares is 68 inches, how long is a side of the larger square?
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=side of small square; =side of large square; = Sum of perimeter of both squares

Divide each side by 4.
Subtract from each side.
Use this to substitute.
Substitute for .

Subtract 289 from each side.
Divide each side by -34.
The side of the shorter square is 8 inches.

Divide each side by 4.
ANSWER: The side of the larger square is 9 inches
CHECK:
Difference in area is 17 square inches.

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