SOLUTION: a six foot high,conical wall tank is filled to the top.When a valve at the bottom of the tank is open,the height h,in feet of the water in the tank is given by h=(88.18-3.18t)^2/5

Question 955618: a six foot high,conical wall tank is filled to the top.When a valve at the bottom of the tank is open,the height h,in feet of the water in the tank is given by h=(88.18-3.18t)^2/5 where t is the time in seconds after the valve is opened. Round answer to the nearest tenth find theheight of water 14 seconds after the valve is opened. and how long will it take to empty the tank?

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
a six foot high,conical wall tank is filled to the top.
When a valve at the bottom of the tank is open, the height h, in feet of the water in the tank is given by
h = (88.18-3.18t)^2/5 where t is the time in seconds after the valve is opened. Round answer to the nearest tenth find the height of water 14 seconds after the valve is opened.
h = (88.18-(3.18*14))^2/5
h = (88.18 - 44.52)^(2/5)
h = 43.66^(2/5)
h = 4.5 ft
:
how long will it take to empty the tank?
h=0
(88.18-(3.18t))^2/5 = 0
We want the value inside the brackets to = 0; when this happens, we can ignore the exponent
88.18 - 3.18t = 0
-3.18t = -88.18
3.18t = 88.18
t = 88.18/3.18
t = 27.7 sec to empty the tank
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