SOLUTION: Please help me in this question!! The perimeter of a rectangle is 54 centimeters, and it's area is 140 square centimeters. Find the dimensions of the rectangle.

Question 954600: Please help me in this question!!
The perimeter of a rectangle is 54 centimeters, and it's area is 140 square centimeters. Find the dimensions of the rectangle.

Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
P=2(L+W)
54cm=2(L+W)
27cm=L+W
27cm-W=L
A=L*W
Substitute for L.

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=169 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 20, 7. Here's your graph:

W=7cm
ANSWER:The width is 7cm.
L=27cm-W=20 cm ANSWER 2: The length is 20 cm.
CHECK:
A=L*W

.
P=2(L+W)
54cm=2(20cm+7cm)
54cm=2(27cm)
54cm=54cm
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