SOLUTION: A 19-inch rope is to be cut into two pieces so that one piece is 3 inches longer than twice the other. How long is each piece, if a = 2, b = 3, and l = 19?
Algebra.Com
Question 953025: A 19-inch rope is to be cut into two pieces so that one piece is 3 inches longer than twice the other. How long is each piece, if a = 2, b = 3, and l = 19?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
19=A+B
19=A+(2A+3)
19=3A+3
19-3=3A
3A=16
A=16/3
A=5 1/3
B=2(5 1/3)+3=10 2/3+3=13 2/3
PROOF:
19=(5 1/3)+(13 2/3)=19
19=19
RELATED QUESTIONS
if a 22-inch rope is to be cut into 2 pieces so that one is 3 inches longer than twice... (answered by josmiceli)
If a 22 inch rope is to be cut into two pieces so that one piece is 3 inches longer than... (answered by mananth)
If a 22 inch rope is to be cut into two pieces so that one piece is 3 inches longer than... (answered by josmiceli)
A 21-inch rope is to be cut into two pieces so that one piece is 5 inches longer than... (answered by Maths68)
if a 22 inch rope is to be cut into two pieces so the one piece is 3 inches longer than... (answered by josmiceli)
A 22 inch rope is to be cut into two pieces so that one piece is 6 inches longer than... (answered by josmiceli)
Please help me. I am at my wit's end trying to solve this problem. Assistance will be... (answered by mananth)
A 24-inch rope is to be cut into two pieces so that one piece is 5 inches longer than... (answered by josgarithmetic)
A rope that is 18 feet long is cut into two pieces. One piece is 6 feet longer than the... (answered by T-Maree)