SOLUTION: when a 10-in. shell is shot from a mortar at an angle of 75 degrees, the height, y (in feet), of the shell t sec after being shot from the mortar is given by y=-16t^2 +224t and the

SOLUTION: when a 10-in. shell is shot from a mortar at an angle of 75 degrees, the height, y (in feet), of the shell t sec after being shot from the mortar is given by y=-16t^2 +224t and the

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Question 948679: when a 10-in. shell is shot from a mortar at an angle of 75 degrees, the height, y (in feet), of the shell t sec after being shot from the mortar is given by y=-16t^2 +224t and the horizontal distance of the shell from the mortar, x (in feet), is given by x= 63t.
How high is the shell after 3 sec ?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
y=-16t^2 + 224t
Sub 3 for t, that's the height.

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