SOLUTION: The height y (in feet) of a ball thrown by a child is y=-\frac{1}{16}x^2 + 6 x + 3 where x is the horizontal distance in feet from the point at which the ball is thrown. (a) Ho

Question 947307: The height y (in feet) of a ball thrown by a child is
y=-\frac{1}{16}x^2 + 6 x + 3
where x is the horizontal distance in feet from the point at which the ball is thrown.
(a) How high is the ball when it leaves the child's hand? (Hint: Find y when x=0) Your answer is y=
(b) How far from the child does the ball strike the ground?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
y=-\frac{1}{16}x^2 + 6 x + 3
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idk what that means.
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