SOLUTION: The length of each side of a square in 3 inches more than the length of each side of a smaller square. The sum of the areas is 425 inches squared. Find the length of the sides of b

Algebra.Com
Question 946049: The length of each side of a square in 3 inches more than the length of each side of a smaller square. The sum of the areas is 425 inches squared. Find the length of the sides of both triangles.
Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!
Do you mean length of the sides of both squares?
I hope so.
Let be the side of the larger square.





We only need the positive solution.


So then,

First square has length 16, smaller square has length 13.

RELATED QUESTIONS

the sum of the areas of two squares is 234 square inches. Each side of the larger square... (answered by mananth)
The sum of the areas of 2 squares is 53cm^2. The length of the side of the larger square... (answered by mananth)
The length of each side of a square is 3 inches more than the length of each side of a... (answered by josgarithmetic)
The sum of the areas of two squares is 85. the length of a side of the larger square... (answered by edjones)
The length of each side of a square is 3 in. more than the length of each side of a... (answered by ikleyn)
The length of each side of a square is 3 in. more than the length of each side of a... (answered by jim_thompson5910,ikleyn,greenestamps)
The length of each side of a square is 3 in. more than the length of each side of a... (answered by josgarithmetic)
Set up an equation and solve the problem: The sum of the ares of two squares is 4,477... (answered by ankor@dixie-net.com)
The length of each side of a square is 3in more than the length of each side of a smaller (answered by scott8148)