SOLUTION: The length of a rectangle is 3cm greater than its width. The perimeter is 24 cm. Find the dimensions of the rectangle. -----thanks again for all your help-----

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L=W+3
2(W+3)+2W=24
2W+6+2W=24
4W=24-6
4W=18
W=18/4
W=4.5 ANSWER FOR THE WIDTH.
L=4.5+3
L=7.5 ANSWER FOR THE LENGTH.
PROOF
2*4.5=2*7.5=24
9+15=24
24=24

You can put this solution on YOUR website!
Let w be the width of the rectangle and l be the lenght.

Given that w = w and lenght equals three more than w. So l = 3 + w

We know that the perimeter is given by 2l + 2w = P

Substituting for the values of l and w, we get:

2(3 + w) + 2w = 24

6 + 2w + 2w = 24

6 + 4w = 24

4w = 24 - 6

4w = 18

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Thsi gives the width of the rectangle.

Now the length is got by substituing it in l = 3 + w







This gives the lenght..

The width and the lenght of the rectangle can be cross verified by substituting it back in the perimeter equation.



= 15 + 9

= 24

= RHS

Hence, the solution is correct..!!

Happy calculating..

Feel free to get back to me regading any queries that you have in Math

Regards
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