SOLUTION: edwin bends a 48 inch wire to form a recatangle. If the width of the rectangle measures 2 times its length, what is the length of the wire

Question 938434: edwin bends a 48 inch wire to form a recatangle. If the width of the rectangle measures 2 times its length, what is the length of the wire
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi,

     .

2L + 2w = 48in

L + w = 24in  

L + 2L - 24in

3L = 24in

L = 8in  and w = 16in 

And...checking

2L + 2w = 48in 

RELATED QUESTIONS

Christopher cuts a length of wire.  He bends it to form a rectangle that is four times as  (answered by josmiceli,lwsshak3)
a piece of wire 80 cm long is bent to form a rectangle whose length is 3 times its width... (answered by josmiceli)
A wire 105cm long is bent to form a rectangle te ratio of its length to its width is... (answered by Fombitz)
The length of a rectangle is 2 times longer than its width. If the diagonal of the... (answered by macston)
The width of a rectangle is two less than its length. If the area is 48 cm squared, what... (answered by mgmoeab)
A 48 cm long wire is bent to form a rectangle whose length is twice it's width. Find the... (answered by mananth)
the lenght of a rectangle exceeds its width by 2yd. if the perimneter of the recatangle... (answered by Paul,rapaljer)
The length of a rectangle is three less than twice the width.  If the perimeter of the... (answered by Alan3354)
A wire that is 76 inches lonh is bent to form a rectangle. If the length of this... (answered by booklover15)