SOLUTION: find the equation of the diameter of a circle whose endpoints are at (6,11) and (-3,1)

Question 933319: find the equation of the diameter of a circle whose endpoints are at (6,11) and (-3,1)

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find the equation of the diameter of a circle whose endpoints are at (6,11) and (-3,1)
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slope = (11-1)/(6--3) = 10/9
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Form:: y = mx + b
Solve for "b"::
11 = (10/9)*6 + b
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11 = (20/3) + b
b = 13/3
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Equation:
y = (10/9)x + (13/3)
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Cheers,
Stan H.
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