SOLUTION: the length of a rectangle is 180cm greater than its width. were the width 60cm less and the length 90 cm greater, the area would be the same as before. Find the larger side

Question 931564: the length of a rectangle is 180cm greater than its width. were the width 60cm less and the length 90 cm greater, the area would be the same as before. Find the larger side
Answer by Stitch(470) (Show Source): You can put this solution on YOUR website!
The equation for the area of a rectangle is: A = LxW
Equation 1:
Equation 2:
Equation 3:
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Note that the areas of both rectangles are the same so we can set them equal to each other.

From equation 1, we now that L = W + 180.
Plug (W + 180) into the equation for L

Simplify

We can use FOIL on the right side of the equation.
ERROR Algebra::Solver::Engine::invoke_solver_noengine: solver not defined for name 'foil'.

Error occurred executing solver 'foil' .

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Rewrite the equation

Subtract from both sides.

Subtract 180W from both sides.

Add 16200 to both sides.

Divide both sides by 30

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Now plug 540 into equation 1 for W
Equation 1:

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