SOLUTION: So, there's a rectangle named FGHJ. FG(top base) is 4x+11 and GH(right side) is 3x-1. The perimeter is 48. Find x, then find the area of the rectangle. I've tried setting them

Question 922576: So, there's a rectangle named FGHJ. FG(top base) is 4x+11 and GH(right side) is 3x-1. The perimeter is 48. Find x, then find the area of the rectangle.
I've tried setting them equal to each other, but that didn't work because they both aren't going to be the same thing.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
L = length
W = width

Let's say the horizontal sides are the length, so . Recall that the parallel sides of a rectangle are congruent.

The vertical sides are the width, so

The perimeter of the rectangle is found by this formula where P is the perimeter, L is the length, W is the width.

Plug in , , and . Solve for x.

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Let me know if that helps or not. Thanks.

If you need more help, feel free to email me at jim_thompson5910@hotmail.com

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