SOLUTION: The length of a rectangle is 3 units less than 6 times its width. The area of the rectangle is 145 square units. Which of the following equations can be used to find w, the width o

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Question 922428: The length of a rectangle is 3 units less than 6 times its width. The area of the rectangle is 145 square units. Which of the following equations can be used to find w, the width of the rectangle?
A. 7w - 3 = 145
B. 6w^2 - 18w = 145
C. 7w - 18 = 145
D. 6w^2 - 3w = 145

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
.
A = Lw
(6w-3)w = 145
6w^2 -3w = 145
.........
6w^2 - 3w - 145 = 0
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=3489 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 5.17231314187412, -4.67231314187412. Here's your graph:

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