SOLUTION: The square root of the sum of 2 consecutive odd integers is 1 less than 3 times the smaller integer. Find the integers..Pls help.thanks a lot.

Algebra.Com
Question 921690: The square root of the sum of 2 consecutive odd integers is 1 less than 3 times the smaller integer. Find the integers..Pls help.thanks a lot.
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
The square root of the sum of 2 consecutive odd integers is 1 less than 3 times the smaller integer. Find the integers
------------


Square both sides

Now it's a quadratic

(9n + 1)*(n - 1) = 0
n = 1
-------

RELATED QUESTIONS

The sum of 2 consecutive odd integers is 16 more than the 4 times the smaller integer.... (answered by math_helper)
there are three consecutive odd integers and sum of smaller is 49 less than 3 times... (answered by oberobic)
I have 5 questions 1.the greater of two consecutive integers is 10 less than twice the (answered by rmromero)
one third of the sum of two consecutive odd integers is 5 less than the smaller integer.... (answered by drk)
One third the sum of two consecutive odd integers is five less than the smaller integer.... (answered by vleith)
the product of 2 consecutive odd integers is 42 more than 3 times the smaller integer.... (answered by CubeyThePenguin)
The sum of 3 consecutive odd integers is 12 less than 3 times the middle... (answered by josgarithmetic,MathTherapy)
The sum of 3 consecutive odd integers is 17 less than 4 times the smallest integer (answered by CubeyThePenguin)
find three consecutive odd integers such that the square of the largest integer is 1 more (answered by harpazo)