SOLUTION: The length of a rectangle is 3 feet more than twice its width. The area is 65 square feet. Find the dimensions of the rectangle using the quadratic formula.

Algebra.Com
Question 920918: The length of a rectangle is 3 feet more than twice its width. The area is 65 square feet. Find the dimensions of the rectangle using the quadratic formula.
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
.
A = Lw
(2w+3)w = 65 ft^2
2w^2 + 3w - 65 = 0 (Tossing out the negative solution for unit measure)
(2w + 13)(w -5 ) = 0
w = 5ft and L = 13ft

RELATED QUESTIONS

the width of a rectangle is 6 feet less than twice its length. If its area is 108 square... (answered by TimothyLamb,srinivas.g)
The length of a rectangle is 3 more than twice the width. The area is 44 square feet.... (answered by jojo14344)
the length of a rectangle is 3 feet more than twice the width. the area is 90 square... (answered by ReadingBoosters)
The length of a rectangle is 3 feet more than the width. The area of the rectangle is 54... (answered by checkley77)
The length of a rectangle is four feet more than twice its width. If the area of the... (answered by Fombitz,MathTherapy)
The length of a rectangle is 3 feet longer than twice the width. If the area is 54 square (answered by TimothyLamb)
the length of a rectangle is 4 feet less than twice its width. If the area of the... (answered by 2897696)
The area of a rectangle is 70 square feet. If the length is four more than twice the... (answered by TimothyLamb)
A rectangle has an area of 54 square feet. The length is 3 feet more than the width. Find (answered by vleith)