SOLUTION: The arena of a rectangle is x^2+3x+10. Find the dimensions of the rectangle in terms of x.
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Question 881266: The arena of a rectangle is x^2+3x+10. Find the dimensions of the rectangle in terms of x.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The arena of a rectangle is x^2+3x+10. Find the dimensions of the rectangle in terms of x.
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arena?
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Not enough info.
could be x by (x^2+3x+10)/x
could be x^2 by (x^2+3x+10)/x^2
could be 3x by (x^2+3x+10)/(3x)
etc
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