SOLUTION: The length of a rectangle is 10 feet longer than it is wide. If each side is increased 10 feet, then the area is multiplied by 2. What was the size of the original rectangle?

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Question 880432: The length of a rectangle is 10 feet longer than it is wide. If each side is increased 10 feet, then the area is multiplied by 2. What was the size of the original rectangle?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
w and L, width and length.
, for the first part of the description.

Each side is increased by 10 feet.
the increased width;
, the increased length.

The increased dimensions makes area become , the area of the original rectangle multiplied by 2.

Find original w and L.
Original area, .
Increased area, .

We were given that increased area equals two times the original area:




D=100-4*(-20)=100+80=180, sqrt(180)=sqrt(3*6*2*5)=sqrt(3*3*2*2*5)=6sqrt(5).

Original width, .


Original length, .

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
The length of a rectangle is 10 feet longer than it is wide. If each side is increased 10 feet, then the area is multiplied by 2. What was the size of the original rectangle?

Width of original rectangle: feet
Length of original rectangle: feet
Area of original rectangle:
You can do the check!!
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