SOLUTION: Find the coordinates of a point equidistant from (-2, 8) (1,-1) and (-8,-4) Please show your solution. Thank you.

SOLUTION: Find the coordinates of a point equidistant from (-2, 8) (1,-1) and (-8,-4) Please show your solution. Thank you.

Algebra.Com

Question 864937: Find the coordinates of a point equidistant from (-2, 8) (1,-1) and (-8,-4) Please show your solution. Thank you.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
Those points are the vertices of right isosceles triangle.
In a right triangle, the midpoint of the hypotenuse is equidistant from the three polygon vertices.
The hypotenuse is (-2, 8) to (-8,-4)
The midpont (-5, 2) it is 3sqrt(5) from each vertex
RELATED QUESTIONS
B. Magnitude of Vectors (Trigonometry) 1. Find the magnitude of the Vector ML if point M (answered by ikleyn)

the coordinate of a point P is twice the abscissa. this point is equidistant from (-3,1)... (answered by stanbon)

FIND THE COORDINATES OF THE POINT EQUIDISTANT FROM (1, -6), (5, -6) AND (6, 1) (answered by ikleyn)

Find the coordinates of the point on the line y = x - 9 which is equidistant from the... (answered by Alan3354)

TRIGONOMETRY B. Magnitude of Vectors 1. Find the magnitude of the Vector ML if point M... (answered by Alan3354)

Find coordinates for the point equidistant from (2,1) (2,-4) (-3,1) Please i really... (answered by MathLover1,Edwin McCravy,josmiceli)

find the point of the y-axis that is equidistant from A(-4,-2) A(3,1). Thank... (answered by josmiceli)

locate the point equidistant from A = (3,8), B = (5,2) and C =... (answered by josgarithmetic,ikleyn)

P(x,2x) The ordinate of a point P is twice the abscissa. This point is equidistant... (answered by Theo)