SOLUTION: Find the area of an isoceles trapeziod that has a perimeter of 90 meters. The longer base is 5 meters less than twice the length of the shorter base. The length of each leg is 3 me
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Question 863534: Find the area of an isoceles trapeziod that has a perimeter of 90 meters. The longer base is 5 meters less than twice the length of the shorter base. The length of each leg is 3 meters less than the length of the shorter base.
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
b, bottom base, the longer base
t, top base
y, each side
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and
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SUM of the lengths of the sides is 90 meters, according to "perimeter of 90 meters". Notice how b and y are described in terms of t.
.
The base angle at bottom is needed, so that the height can be found. This isosceles trapezoid is composed of two right triangles, one on each side, and a rectangle in the middle. You can draw this figure.
Call the base angle, measure a.
Let h = height of the triangle and also of the trapezoid.
The bottom leg OF EACH RIGHT TRIANGLE is ; and since you have a formula for b and have now found t, each bottom leg of the right triangle is
, leg length of a right triangle.
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The hypotenuse of each right triangle is y.
, and a formula for y is already described in terms of t.
degrees
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-----The HEIGHT of the trapezoid.
AREA:
.... you can finish this computation.
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