SOLUTION: The length of a rectangle is 1 inch more than twice its width. If the perimeter of the rectangle is 20 inches, what are the dimensions of the rectangle?

Question 863020: The length of a rectangle is 1 inch more than twice its width. If the perimeter of the rectangle is 20 inches, what are the dimensions of the rectangle?
Answer by JulietG(1812) (Show Source): You can put this solution on YOUR website!
The perimeter is a fence around the rectangle. It will requires two pieces of width and two pieces of length. P = 2W + 2L
P = 20" [the perimeter of the rectangle is 20 inches]
L = 2W+1 [The length of a rectangle is 1 inch more than twice its width]
Substitute the known value of L into the first equation.
P = 2W + 2(2W+1)
20 = 2W + 4W + 2
20 = 6W + 2
Subtract 2 from each side
18 = 6W
Divide each side by 6
3 = W
.
If the width is 3, then the length is twice that + 1, or 7.
Let's add them together to prove.
3 + 3 + 7 + 7 = 20
20 = 20
Success!
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