SOLUTION: the height of a triangle is 4 feet less than the base. The area of the triangle is 198 square feet. Fine the length of the base and the height of the triangle 1/2(x(x+4)=198

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Question 860504: the height of a triangle is 4 feet less than the base. The area of the triangle is 198 square feet. Fine the length of the base and the height of the triangle

1/2(x(x+4)=198
1/2(x^2+4)=198
x^2+4x-396
I don't know whats next

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
Question States***height of a triangle is 4 feet less than the base
1/2(x(x-4)=198
1/2(x^2-4x)=198
x^2-4x-396 = 0 |Hint: sqrt(396) = ~19.9 (2*8) ends in 6
(x -22)(x+18) = 0 (Tossing out the negative solution for unit measure)
x = 22ft, the width. Then length is 18ft
Or quadratic Eq always works
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=1600 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 22, -18. Here's your graph:

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