SOLUTION: when 3 inches are added to each side of a square, its area increases by 57 square inches. What was the perimeter of the initial square?

Algebra.Com
Question 859523: when 3 inches are added to each side of a square, its area increases by 57 square inches. What was the perimeter of the initial square?
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
Let x represent length of each side of original square
(x+3)^2 = x^2 + 57in^2
x^2 + 6x + 9 = x^2 + 57
6x = 48
x = 8in and P = 4*8in = 32in

RELATED QUESTIONS

when 2 inches are added to each side of a square its area increase by 44 square... (answered by checkley79)
If the length of a rectangle is decreased by 2 inches and its width is increased by 2... (answered by ankor@dixie-net.com)
the number of inches in the perimeter of a square is 3 more than the number of square... (answered by azhou4,richwmiller)
the number of inches in the perimeter of a square is 3 more than the number of square... (answered by KMST)
Each side of a square is increased 5 inches. When this happens, the area is multiplied by (answered by richwmiller)
Each side of a square is increased 6 inches. When this happens, the area is multiplied by (answered by macston)
Each side of a square is increased 4 inches. When this happens, the area is multiplied by (answered by ikleyn)
Each side of a square is increased 8 inches. When this happens, the area is multiplied by (answered by ikleyn)
Each side of a square is increased 9 inches. When this happens, the area is multiplied by (answered by ikleyn,Theo,greenestamps)