Hi,

Perhaps this picture will help: 

the 'h' is a 'leg', other leg = 24 (h bisects the base)

hypotenuse = 26



line segment of Height to the base bisects the base (base = 48)

Therefore: 26^2 - 24^2 = h^2 = 100, h = 10

 A =  = 240

 Find the base of the other triangle 

 A = 240 = 

    480= 

    480^2/b^2 = 26^2 - (b^2/4

    b^4  -4(26^2)b^2 + 4(480^2)  Let x = b^2

    x^2 - 2704x + - 921600

x = 400 0r x = 2304

 b = 20  0r b = 48

the base of the other triangle is 20

CHECKING our answer***

 26^2 -10^2 = 576= h^2,   h = 24   AND  

Wish You the Best in your Studies.

 

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