SOLUTION: The perimeter of a lot is 190 meters. The width is one-fouth the length. Find the dimensions. This is what I'm doing: W=1/4L 2L+2W=190 2L+2(1/4L)=190 2L+1/2L=190 2 1/2L=1

Question 853578: The perimeter of a lot is 190 meters. The width is one-fouth the length. Find the dimensions.
This is what I'm doing:
W=1/4L
2L+2W=190
2L+2(1/4L)=190
2L+1/2L=190
2 1/2L=190
L= 47 1/2
I looked at my answer key and it says the dimensions are L=76 and W=19. What did I do wrong?

Answer by rvfer(117) (Show Source): You can put this solution on YOUR website!
p=2l+2w
190=2l+2(0.25l)
190=2l+0.5l
190=2.5l
190/2.5=l
l=76
0.25l=19 =
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