# SOLUTION: The area of a rectangle is 18 square meters. When the length is increased by 2 meters and the width by 3 meters the area becames 48 square meters. Find the dimensions of the smalle

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Geometry -> SOLUTION: The area of a rectangle is 18 square meters. When the length is increased by 2 meters and the width by 3 meters the area becames 48 square meters. Find the dimensions of the smalle      Log On

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 Question 84840This question is from textbook Elementry and Entermeditate Algebra : The area of a rectangle is 18 square meters. When the length is increased by 2 meters and the width by 3 meters the area becames 48 square meters. Find the dimensions of the smaller triangle. Just by looking at this problem I can tell the answer is 6 meters and 3 meters. But I can not figure out how to set up the forula. I tried (m+2)(m+3)=48 I then used FOIL then used the quadratic formula but it didn't work. Can anybody help Thanks.This question is from textbook Elementry and Entermeditate Algebra Answer by josmiceli(9669)   (Show Source): You can put this solution on YOUR website!w = width l = length divide both sides by l multiply both sides by l divide both sides by 3 Two values of l make this equation true, l = 2 and l = 6 Going back to , if l = 2 w = 9 Then going back to This is true, so those values work ----------------------- If l = 6, then w = 3 This is true also, so both l = 2, w = 9 and l = 6 w = 3 are both solutions. Take your pick