SOLUTION: the larger of two numbers is 16 more than the smaller. when added together their sum is 6 less than 3 times the smaller. what are the numbers?
(16 + a) + b = 3b -6
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Question 847821: the larger of two numbers is 16 more than the smaller. when added together their sum is 6 less than 3 times the smaller. what are the numbers?
(16 + a) + b = 3b -6
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Numbers a and b, .
and ; in other words, you start with two equations.
Simplify the a+b equation.
.
Put the a-b equation into the same form.
.
You could have skipped most of that once you had the two equations translated from the description, and then continued with a substitution method to find a and b; but now you also have an equivalent system of equations for which the Elimination Method would be convenient.
-
Subtract one equation from the other to eliminate b:
... which will give you.....?
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