SOLUTION: Please help me solve this.
Suppose that the width of a square is three times the width of a second square. How do the areas of the squares compare? Why?
Algebra.Com
Question 829020: Please help me solve this.
Suppose that the width of a square is three times the width of a second square. How do the areas of the squares compare? Why?
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
The area of a square is the square of its width.
Now if you change the width to 3 times the original
What happens to the area of the new square?
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