SOLUTION: The length of a rectangle is 1 cm more than 4 times its width. If the area of the rectangle is 72 cm^2, find the dimensions of the rectangle to the nearest thousandth. Thanks

Question 82346: The length of a rectangle is 1 cm more than 4 times its width. If the area of the rectangle is 72 cm^2, find the dimensions of the rectangle to the nearest thousandth.

Thanks.
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
Let W=width of rectangle
Then length=4W+1
Area(A) of rectangle=Length*Width=W*(4W+1)
Now we are told that:
W*(4W+1)=72 get rid of parens
4W^2+W=72 subtract 72 from both sides
4W^2+W-72=72-72 or
4W^2+W-72=0 quadratic in standard form. We'll use the quadratic formula:

cm ----------------------width of rectangle
cm---------------------length of rectangle
Discount negative value for W. Lengths are positive.
CK
A=L*W=(4.120)(17.480)=72 cm^2
~72 cm^2=72 cm^2

Hope this helps----ptaylor

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