SOLUTION: the backyard of a neighbor's house is rectangular, and its length is 5 feet more than its width. if the area of the yard is 500 square feet, how much fencing would be required to e

Question 821626: the backyard of a neighbor's house is rectangular, and its length is 5 feet more than its width. if the area of the yard is 500 square feet, how much fencing would be required to enclose the yard
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
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x = y + 5
xy = 500
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xy = 500
(y + 5)y = 500
yy + 5y - 500 = 0
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the above quadratic equation is in standard form, with a=1, b=5, and c=-500
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
1 5 -500
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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the two real roots (i.e. the two x-intercepts), of the quadratic are:
y = 20
y = -25
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negative width doesn't make sense so use the positive root:
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answer:
w = 20 ft
L = 25 ft
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Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
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Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
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Solve systems of linear equations up to 6-equations 6-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php
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