SOLUTION: a ball is thrown straight upward at an initial speed of 240 feet per second. From physics, we know that the ball will reach a height of h feet after t seconds where h and t are rel
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Question 820460: a ball is thrown straight upward at an initial speed of 240 feet per second. From physics, we know that the ball will reach a height of h feet after t seconds where h and t are related by the following formula: h=-16t^2+240t. when did the ball hit the ground?
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
h = -16t^2 + 240t
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the above quadratic equation is in standard form, with a=-16, b=240, and c=0
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to solve the quadratic equation, by using the quadratic formula, plug this:
-16 240 0
into this: https://sooeet.com/math/quadratic-equation-solver.php
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the two real roots (i.e. the two x-intercepts), of the quadratic are:
t = 0
t = 15
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answer:
ball hits the ground 15 seconds after being thrown
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Solve quadratic equations, quadratic formula:
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Solve systems of linear equations up to 6-equations 6-variables:
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