SOLUTION: could you please help me solve this problem : The length of a rectangle is 6 times longer than the width. The perimeter is 42. what is the width ? This is what I have tried: Per

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Question 809625: could you please help me solve this problem : The length of a rectangle is 6 times longer than the width. The perimeter is 42. what is the width ?
This is what I have tried: Perimeter = 2l + 2w
2(6*w)+2w=42
12+2w+2w+42

Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!
L for length
w for width

and directly from the description.

Substituting for L in the perimeter equation,


meaning that

Your mistake was from:

Which should have gone,


, and as shown already...

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