SOLUTION: The perimeter of a rectangular lot is 190 ft. The width of the lot is 15 ft. more than the lenght. What are the dimensions of the lot?

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Question 8096: The perimeter of a rectangular lot is 190 ft. The width of the lot is 15 ft. more than the lenght. What are the dimensions of the lot?
Answer by CharStar(110) About Me  (Show Source):
You can put this solution on YOUR website!
Perimeter of a Triangle is P=2(L+w)
Length = x
Width = x+15
Equation is 190=2%28x%2Bx%2B15%29
190=2%282x%2B15%29
190=4x%2B30
160=4x
40=x
Length = 40
Width = 40+15=55
Perimeter = 2(40+55)= 190
I hope that helps you
CharStar