SOLUTION: The perimeter of a rectangle is 110 feet. Find the length and width if the width is 5 less than the length.

Algebra.Com
Question 793165: The perimeter of a rectangle is 110 feet. Find the length and width if the width is 5 less than the length.
Answer by waynest(281)   (Show Source): You can put this solution on YOUR website!
width = L -5
length = L
perimeter = 110
2L + 2(L - 5) = 110
2L + 2L - 10 = 110
4L - 10 + 10 = 110 + 10
4L = 120
4L/4 = 120/4
L = 30
check:
2(30) + 2(30 -5) = 110
60 + 2(25) = 110
60 + 50 = 110
110 = 110

RELATED QUESTIONS

The length of a rectangle if 4 feet less than 4 times the width. If the perimeter is 132, (answered by rfer)
Suppose the perimeter of a rectangle is 200 feet and the length of the rectangle is 5... (answered by mananth)
The perimeter of a rectangle is 80 feet, and it's length is 5 feet less than twice its... (answered by algebrahouse.com)
The length of a rectangle is 2 feet less than twice its width. If the perimeter is 26... (answered by Cromlix)
if the width of a rectangle is four feet less than the length and the perimeter is 152... (answered by macston)
The length of a rectangle is 3 feet less than twice its width and the perimeter is 72... (answered by stanbon)
The length of a rectangle is 7 feet less than twice the width. The perimeter is 64 feet.... (answered by ewatrrr)
The width of a rectangle is 5 feet less than its length. The perimeter of the rectangle... (answered by ewatrrr)
Algebra 2 word problem: The width of the rectangle is 3 feet less than its length. The... (answered by stanbon)