SOLUTION: Question: The Hypotenuse of a right triangle exceeds the longer of the two legs by 2. If the perimeter of the triangle is 40, find the lengths of the sides of the triangle. I

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Question 75820: Question: The Hypotenuse of a right triangle exceeds the longer of the two legs by 2. If the perimeter of the triangle is 40, find the lengths of the sides of the triangle.
I came up with the answer, but I have to show an algebraic solution which I did not do.

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Let c=hypotenuse, a=longer leg, b=other leg
Since the hypotenuse exceeds the longer leg by 2, it is 2 units more than the longer leg. In other words:

Since the perimeter is 40, we can find the other leg by the perimeter formula
where P is the perimeter and a,b,c, are the sides of the triangle

Substitute a+2 into c
Since the missing side (b) can be found by Pytagoreans Thereom, we can say


Solve for b
Substitute a+2 into c


Now plug in in for b to complete the equation



Square both sides

Get all terms to one side
Now plug your quadratic into the quadratic formula to find a (sorry the solver wouldn't format):
if we use a calculator, we get:
or
Now lets find c

Let a=24

Since 24+26=50 which is over 40, 24 is not our answer

Let a=24

Now find b





So the sides are:
a=15,b=8,c=17


Check:
Use the perimeter formula to check
Plug in a=15,b=8,c=17
works

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