SOLUTION: Q1Q3 IN A SQUARE ABCD ,AB=(2x+3)CM BC =(3x-5)CM .FIND THE PERIMETER OF ABCD.''.

Question 755218: Q1Q3 IN A SQUARE ABCD ,AB=(2x+3)CM BC =(3x-5)CM .FIND THE PERIMETER OF ABCD.''.

Found 2 solutions by dkppathak, MathTherapy:
Answer by dkppathak(439) (Show Source): You can put this solution on YOUR website!
P = 2(l+b)
perimeter =2(2x+3+3x-5)
=2(5x-2)
=10x-4 cm
PERIMETER OF ABCD IS 10X-4 CM
Answer by MathTherapy(10557) (Show Source): You can put this solution on YOUR website!
Q1Q3 IN A SQUARE ABCD ,AB=(2x+3)CM BC =(3x-5)CM .FIND THE PERIMETER OF ABCD.''

Being a square with one side equaling 2x + 3, and the other, 3x - 5, then:

2x + 3 = 3x - 5

2x - 3x = - 5 - 3

- x = - 8

x = , or 8

One side of square = 2(8) + 3, or 16 + 3, or 19 cm

Perimeter = 19(4), or cm
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