# SOLUTION: Here is the question. I even know the answer. However, I do not know how to solve it. "A woman walks home by traveling 20 meters north, 25 meters east, and then 5 more meters

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Geometry -> SOLUTION: Here is the question. I even know the answer. However, I do not know how to solve it. "A woman walks home by traveling 20 meters north, 25 meters east, and then 5 more meters       Log On

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 Click here to see ALL problems on Geometry Word Problems Question 75470: Here is the question. I even know the answer. However, I do not know how to solve it. "A woman walks home by traveling 20 meters north, 25 meters east, and then 5 more meters north. If she could walk home along a straight line, how many fewer meters would she need to walk? Round your answer to the nearest hundredth." The answer is 14.64 meters. Answer by checkley75(3666)   (Show Source): You can put this solution on YOUR website!THE BEST WAY TO SOLVE THIS PROBLEM IS WITH A GRAPH USING X & Y COORDINATES. START AT THE INTERSECTION (0,0), GO UP (NORTH) 25 UNITS, THEN GO 20 UNITES TO THE RIGHT (EAST) THEN ANOTHER 5 UP (NORTH). YOU ARE NOW AT (25,25). NOW DRAW A LINE FROM HERE TO THE ORIGIN (0,0) AND YOU HAVE THE HYPOTENUSE OF A 25 BY 25 RIGHT TRIANGLE. USING THE FORMULA A^2+B^2=C^2 WE HAVE 25^2+25^2=C^2 625+625=C^2 1250=C^2 C=35.36 METERS IS THE LENGTH OF THE WALK HOME. 50-35.36=14.64 METERS IS THE DIFFERENCE BETWEEN THE TWO WALKS.